Jan 162016

Also here is ”Distances to the Planets” also by His Grace Mayesa dasa

Part One to Part Thirteen


Calculating the sun is done with the help of the number referred to in 5th Canto as the second axle. That number is 31,500,000

Vayu Purana tells us diameter of sun is 252,000,000

Diameter is twice radius therefore radius is 126,000,000

Twice radius times Pi or 3.141592654 is circumference therefore sun’s circumference is 791,681,348.7 But sun has fast, slow and moderate speed.

Therefore sun moves further around us than 791,681,348.7 and less also. That number is 31,500,000 Here is the formula:

137,509,870.8 X 31,500,000 / (21,600 / 2 / pI) = 126,000,000

126,000,000 x 31,500,000 / (21,600 / 2 / pI) = 115,453,530

Theses are radiuses of the sun.

For each multiply by 2 and by Pi to get circumferences. We learn that the Sun’s chariot is 28,800,000 That is sun’s travel in a Muhurta.

There are 30 muhurtas in a day so Sun’s greatest travel is 864,000,000. The sun travels faster over greater distance around earth planet. Similarly the sun has a very slow path which is 725,415,924.2

We learn in Bhagavatam that there are 7 islands and 7 oceans below us ( not on this planet) When we calculate them and subtract the last ocean and half of Plaksa dvipa

5th Canto says sun is at middle path in the center of Manasottara mountain in the center of Plaksadvipa) we get sun at 126,000,000 radius as we should and as is confirmed by Vayu purana.

Does sun continue upwards to lesser number? Yes 5th Canto mentions 760,800,000 which is beyond middle point.

By mathematics we can understand then the path of the sun from 864,000,000 at 23.60928249 degrees south to 725,415,923.2 which is 23.60928249 degrees north. This movement of the sun causes seasons.


Because the sun is gathering water from our planet and other planets as well up to Dhruvaloka ( according to Matsya Purana) Then the sun having gathered water for six months expels water for six months.

Modern scientists cannot fathom that the sun is expanding. When we view the Sun through a telescope it appears to be nothing but gasses. This is water boiling surrounding the sun. Scientists think the sun is nothing but gasses but we get information that the sun is having a civilization there.

Krsna mentions speaking Bhagavad-Gita previously to the Sun-god.

To understand the great distance to sun we divide 864,000,000 by 2 and by Pi and by cosine 23.60928249 which tells us that sun reaches to 150,071,147.4 miles away from us at greatest distance.

Sukadeva thus reveals the sun’s motion to us in the Srimad Bhagavatam. Of course sun has more than three speeds as it gradually spirals up and down.

Sukadeva is not elaborating on the path of other planets but if we approach the 5th canto properly (if we know how mathematically) we will find not only the distances to the planets mentioned but to non-moving bodies as well.

The Distances to the Planets From 5th Canto by Mayesa dasa

Part Two

We have seen in part one that Sukadeva Gosvami has given us the distances and movements of the sun planet in the elaborate chapter “Movement of the Sun” But from this point on Sukadeva simply speaks of other universal objects as “above the earth” or “below the sun”. In this way, we must proceed assuming that some sort of mathematical formula is indicated.

One may certainly object that we must alter or use these numbers given in Srimad Bhagavatam but as no distance or declination is indicated in the text for any object other than the sun it is impossible to proceed without the consideration that Srimad Bhagavatam involves a formula in order to uncover the subsequent objects.

This being true, not only Moon, Venus, Mercury etc can be calculated by mathematical formula but sun as well.

We have seen how 31,500,000 can be used but that “second axle” is specifically for calculating the sun. We can or could transform that axle to an axle for the moon but we have been provided a different mathematical formula which will give us everything, including beginning with the sun.

Below the earth planet is a large body of 7 islands and 7 oceans. The 5th Canto says the sun is 800,000 above earth. We cannot make it any easier, unfortunately to understand without addressing one by one the elements of the mathematical formula which will unveil the movement and distance of the planets.

First 24,902 is the size of earth planet. Second our 5th Canto text says “above the earth by 800,000 miles” So we add 24,902 + 800,000 = 824,902

Now we have a second earth which consists of 7 islands and 7 oceans. Subtracting its last ocean so that we are “above the earth” we divide 824,902 by 952,530,892.3 which is the 7 islands and 7 oceans minus the last ocean.

This will give us a decimal. This decimal number or fraction is now multiplied by a number to give us the sun’s declination.

Fortunately we know what the sun’s declination is. That is 791,681,438.4 / 360 X 23.60928249

So, we can divide that sum by our decimal. This will give us a number 599….. That number, 599…. is another planet’s circumference.

In other words, The Srimad Bhagavatam 5th Canto is a “puzzle” This is necessarily so because we are given no declinations.

We can look up in astronomy works (modern and ancient) the declination of moon, Venus, Mercury, Mars, Jupiter, Saturn, constellations, 7 sages and Dhruvaloka but we have no possible clue to distance and declination of heavenly realms or subterranean realms. Therefore it has to be clearly understood that to find these things the numbers must be provided to us either by another Purana (because they are not openly provided in 5th Canto Bhagavatam) or they “must” be obtainable by a mathematical process.

This shall become clear as we proceed.

Distances to the Planets

Part Three

Moon and Constellations

Our calculation for the sun looks like this 824,902 / 952,530,892.3 = .000866011 X 5,995,249,931 = 5,191,952.388

The number 5,995,249,931 is the circumference of a higher planet and the number 51,919,523.88 is the declination of the sun.

When we divide 51,919,523.88 by 23.60928249 and multiply by 360 we get 791,681,348.4

We will now look at the moon and the constellations (that will help us to understand how 5,995,249,931 is the circumference of a higher planet.)

The moon is said to be 800,000 miles above the sun and we already know sun is 800,000 miles above the earth. So we add 24,902 + 800,000 + 800,000 = 1,624,902 / 952,530,892.3 = .001715879

Now we need a circumference of an orbiting planet to multiply by this number to give us the declination of the moon. The circumference of Sivaloka (Siva has several planets) is 2,215,775,280. This shall be discussed later on in 5th Canto.

.001715879 X 2,215,775,280 = 3,779,843.481/ This number 3,779,843 is the declination of the moon at 18.25 degrees

So divide 3,779,643.481 by 18.25 and multiply by 360 to get moon’s circumference of 745,612,960.7

To get the circumference of the constellations we follow the prescription for adding 4,000,000 to 24,902 and divide by 952,530,892.3 = .004225482

The universe has a circumference, which we will multiply this figure by to get the declination of the constellations.

The universe is 12,566,370,610 so 12,566,370,610 X .004225482 = 53,098,972.84

This is the declination of the constellations at 8 degrees. So 53,098,972.84 / 8 X 360 = 2,389,453,778

Now we can understand Canin Majoris or Sivaloka at negative 21.97 degrees

We multiply the constellations 2,389,453,778 X cos 21.97999992 = 2,215,775,280 (Although Sivaloka is below celestial zero or our equator we do not employ negative numbers for math)

Now we can also better understand the number 5,995,249,931 which we said was a higher planet’s circumference.

Tapaloka, Satyaloka, Janaloka and Maharloka lie at the extreme north in our universe. The number 5,995,249,931 is perhaps Maharloka at 61.5 degrees on the circle of the universe.

So 12,566,370,610 X cos (61.50468943 = 5,995,249,931

What have we learned? We have found sun, moon, constellations, Sivaloka, Maharloka in three calculations.

When we diagram the moon and sun together we shall learn something else extraordinary. We shall see that when moon is at celestial zero and sun at 23.6 degrees north moon is further away from us than the sun.

As we work these numbers we shall inevitably make some small error. The formula cleverly accounts for errors and allows us to perfect everything in its calculations for the subterranean planets.

The Distances of the Planets by Mayesa dasa

Part Four


Before we attack the numbers for Venus we should remember that we are working with a system that is designed by an intelligent brahmana or more than that not to “find” the planets but to encapsulate or encode them in a system.

That is why the round figures of 800,000 or 16,000,000 are used (though we have already changed a measurement called yojana to 8 miles) To make it more plain, the distances were known and then the system developed.

Venus is adding to our previous number of 4,000,000 the number 1,600,000 and also the earth planet, which is 24,902 This is stated in the Bhagavatam itself and we are following directions. Then divide by 952,530,892.3 = .005905217

Now we are looking for a number to multiply by our decimal number which will give us the declination of Venus, however we will need two numbers for two separate declinations because Venus travels around the sun as Venus travels around the earth planet.

So first we multiply .005905217 by 1,064,464,461 to get 62,858,936.31

That is declination of Venus so to get the circumference we divide 62,858,936.31 by 27.8 and multiply by 360 = 81,400,061.41

This is good as the circumference is beyond the sun’s circumference of 791,681,348.4

But we also need a circumference for Venus inside the Sun’s circumference (Bhagavatam text for Venus says Venus sometimes travels behind and sometimes in front of the sun)

So our second multiplication is as follows: .005905217 X 1,006,090,881 = 5,941,184.974 As before we now divide this by Venus’s declination of 27.8 and multiply by 360 = 769,362,083. If we wish we can subtract 769,362,083 from 814,000,614.1 to get the circumference of Venus around the sun itself. In other words, Venus revolves around earth as does the sun but Venus also revolves around the sun at the same time.

The numbers we used to multiply by the decimal number will prove later to be numbers of other planetary circumferences. Mercury is located in an even more spectacular way.

The Distances of the Planets by Mayesa dasa

Part Five


Before we find the distance of Mercury we must understand something about the Moon. The Moon travels 346.823 degrees of a circle around the earth everyday.

The sun travels 360 degrees everyday but not the moon. Therefore the moon has two circumferences-its real circumference of 346.823 degrees and its potential circumference. We shall show how to get these but let us understand the concept.

Suppose you have a race track that is 360 miles around and one car travels 360 miles in 24 hours and another car travels 346.823 miles in the same time. This is an apt comparison.

We have found the moon’s circumference as 745,612,960.7 in an earlier chapter. This is the potential circumference or rather this is the path the moon is travelling but only completes 346.823 degrees of it. To derive the actual number of miles Moon travels at zero celestial degrees we divide 745,612,960.7 by 360 and multiply by 346.823 = 718,321,455.2

This is essential to know in order to gain understanding the movement of planets (all planets have their potential and their actual travel) and as we shall see both these numbers will uncover the two distances to Mercury ( as Mercury similar to Venus travels around the sun as it travels around the earth )

We begin by adding (24,902 + 7,200,000) / 952,530,892.3 = .007584953

Now we multiply this decimal by both the potential and actual circumferences of the moon. Thus we derive 5,448,434.477 / 25.6 X 360 = 766,186,098.3 from the actual circumference of the moon.

Our second calculation multiplies the decimal by 745,612,960.7 = 5,655,439.263

/ 25.6 X 360 = 795,296,146.4

Now we have moon at 745,612,960.7 then Venus then mercury then sun then mercury then Venus and we have derived it all from a simple formula.

The Distances to the Planets by Mayesa dasa

Part Six

Mars and Mar’s Opposition

Our distances so far obtained should read as follows:

Moon 755,000,000 (approx)

Venus 769,362,083

Mercury 776,791,454.9

Sun 791,681,438.4

Mercury 806,304,143.7

Venus 814,000,614.1

Mars begins as usual by adding the miles that the text says to add in this case we get 8824902 / 952,530,892.3 = .009264688

We can multiply the lowest circumference of Venus by our decimal which gives us 804,262,037.2 which is Mars’ declination so divide by 27.2 and multiply by 360 = 1,064,464,461 as circumference of Mars.

Mars moves around us completing its revolution in 686 days or something like that but 72 days of that Mars has an opposition. Opposition means Mars apparently reverses course for a short time before correcting itself.

Modern scientists think Sun is center of universe so they can explain Mars feat as the movement of the earth and do. But we who are using this geocentric model cannot say that. For us we have to say that Mars does indeed loop.

It is interesting in the Srimad Bhagavatam text there is mention of Mars moving in a “curved way, sometimes”

Mathematically we can account for this loop by multiplying the lowest circumference for Mercury which is 880763604.8 by our decimal thus giving us a declination of 8,160,000

Next of course we divide by 27.2 and multiply by 360 = 108,000,000

If we subtract 1,064,464,461 from 1,080,000,000 we get 15,535,539 for the size of Mars’ Opposition

One may ask where we are getting our declinations for the planets. That we can get from an Ephemeris which contains the declinations for every day of the main planets and we are using the greatest declination for each planet save the moon which we are using its shortest of 18.2

However we derive them we are deriving the zero degree celestial circumference of the planets.

The distances to the Planets by Mayesa dasa

Part 7


To find Jupiter we begin as always by .

Our earth planet is 24,902 and to get sun we added 800,000 and to get Moon we added 800,000 and to get constellations we added 2,400,000 and for Venus we added 1,600,000 and for Mercury we added 1,600,000 and for Mars we added 1,600,000 and to get Jupiter we add 1600000 which gives us 10,424,902.

Now we divide that by 952,530,892.3 to get .010944424 and now as in all previous equations we must find the correct circumference ( of some planet ) to multiply to derive the declination or arc of Jupiter.

We found that Mars zero celestial circumference was 1064464461. Mars has its highest circumference (or its circumference at 27.2 degrees) which is 946,752,120.4 so let us multiply that by our decimal of .010944424 = 10,361,656.63

Now as we have been doing we divide by the declination which for Jupiter is 23.5 and multiply by 360 to get circumference of Jupiter at zero degrees celestial. That is 1,587,317,611

When a planet, for example Jupiter is 1,587,317,911 at zero degrees celestial we can multiply that by cos 23.5 degrees to find its higher circumference then that planet is at 23.5 degrees.

Cosines can be found by help of calculators the actual number which is cos 23.5 is .917060074

Distances to the Planets by Mayesa dasa

Part 8


To get Saturn’s circumference we first add which gives us 10,424,902 + 1,600,000 and divide by 952,530,892.3 and multiply by Mercury’s lowest circumference which is 894,073,034.7 (Mercury and Venus are like the sun in that they move away from us and closer)

We thus get 11,286,920.68 which is Saturn’s declination

Bow as always we divide by the degrees of Saturn’s greatest declination which is 22.2 and multiply by 360 to get 183,031,146.1

We now have the circumferences of the planets all the way to the Constellations and we shall begin moving to the higher planets. Then the formula works differently to move down the universe.

For getting lower circumferences, as we did for Mercury in Saturn’s equation, we simply divide by cosine

The Distances to the Planets by Mayesa dasa

Part Nine

Calculation of the Seven Sages (Big Dipper ) begins with addition of 8,800,000 more than we had for Saturn so we begin with 20,824,902 / 952,530,892.3 = .021862705

We have said that the constellations are at circumference 2,389,453,778 so if the Seven Sages are at 50 degrees then 2,389,453,778 / 360 X 50 = 331,868,580.3

That is the declination of the Seven Sages (the right declination is very important in this 5th Canto mathematical system) So if we divide by our decimal we will (we assume) have the circumference to some orbiting planetary body.

That math is then 331,868,580.3 / .021862705 = 15,179,666,940

This could be a higher planetary system at 83 degrees (that we will explain shortly)

The Distances to the Planets by Mayesa dasa

Part Ten


Our present day Polestar may or may not be Dhruvaloka. It is a reddish star you can see with your eyes. But actually the real polestar is a little to the side of that star and may not be visible from here.

But we can understand that since the are of North Pole of the universe is there and it is not directly overhead of earth planet then earth planet is not aligned with Meru and the North pole of the universe.

It appears then that the earth planet is a little right (arbitrary use of this word) of center. This would account for planets in our system appearing to have a slight elipse. For the center point in a circle all sides are equally far away but if that center is moved a little to the side the circle is now an ellipse)

We already know the constellations circumference is 2389453778 (and we have used that number to help us find Sivaloka, the Seven Sages and we will be using it again) and we know Dhruvaloka is center north at 90 degrees but earth planet is not perfectly aligned so let us say Dhruvaloka is at 89.17 degrees

We first add 10,400,000 miles to what we had for the Seven sages and begin. 31,224,902 / 952,530,892.3 = .032780986

Now we can work from the constellation circumference thus: 2,389,453,778 / 360 X 89.17 = 591,854,426.1

Now we can simply divide 591,854,426.1 by .032780986 = 1,805,480,854 (This may be the circumference of the lowest point of the Seven Sages)

Now we have Sun, Moon, Venus, Mercury, Mars, Jupiter, Saturn, 7 Sages, Sivaloka, and Dhruvaloka

Frankly I am not yet happy with my calculation for “oppositions” but at present I am satisfied with the consistency of this system.

The Distances to the Planets By Mayesa dasa

Part Eleven


Now we can see that as the ancient Greeks said the planets each have their own path and thus are like ” globes within globes “

This system as we are attempting to lay bare was long in existence but gradually it was lost. Because the Vedic literature was maintained and transferred intact for generations we have access to this system now.

Thus the meaning of “globes within globes” is no better made apparent than our findings for the constellations and 7 sages and Dhruvaloka and Sivaloka all resting at some point on that invisible globe of the constellation’s circumference.

In a similar fashion Maharloka, Janaloka, Tapoloka and Satyaloka lie on the globe of the universe which is 4,000,000,000 X Pi

To find Maharloka add 80,000,000 miles to the number we had for Dhruvaloka which gives us 111,224,902 and divide by 952,530,892.3 = .11676776354

Next, because Maharloka lies connected to the walls of the universe we can divide the universe by 360 and multiply by declination of 61.5 = 2,146,754,979.95

Now we divide by .11676776354 = 18,384,825,699.1 which will be the circumference of another planetary body.

The Distances to the Planets Part Twelve by Mayesa dasa

Higher Realms

For Janaloka we add 160,000,000 miles to Maharloka which gives us 271,224,902 and divide by 952,530,892.3 = .284741318

Then multiply by Venus at it’s lowest circumference, which is 9,202,104,012 and divide by ((4,000,000,000 X Pi) / 360) This tells us that Janaloka is at 75.06375149 degrees

For Tapoloka we add 640,000,000 miles to Janaloka and divide by 952,530,892.3 = .956635537

Now multiply by circumference for constellations which is 2,389,453,778 = 2,285,836,398

Now divide by universe divided by 360 or

(4,000,000,000 X Pi ) / 360 ) = 65.48438913 which means Tapoloka is at 65 degrees

When we say that now we know what is the degree we can know circumference by multiplying the circumference of the universe by cos (75.06375149 or by cos (65.48438913 respectively for Janaloka and Tapoloka which gives us 3,238,908,200 for Janaloka and 5,214,304,353 for Tapoloka

Distances to the Planets by Mayesa dasa

Part Thirteen


Perhaps the degrees at which I have placed Janaloka and Tapoloka should be reversed but we shall plunge ahead so that we can get a sense of the whole system, then any problems can be adjusted.

For Satyaloka we add 960,000,000 miles to Tapoloka and divide by 952,530,892.3 = 1.964476866

Now let us multiply by 1,455,665,606 which is Jupiter’s highest circumference = 2,859,621,408

Now divide by ((4,000,000,000 X Pi) / 360 ) = 81.92211885 degrees

One who is mathematician and is following along will understand that we are working with what is called “process of elimination” This whole system will have to be further refined after we have it all in place.

Finally we come to Vaikuntha. For Vaikuntha we add 209,600,000 and divide by 952,530,892.3 = 2.184522223

We can know what is the universe’s exterior circumference. That is the size of universe (4,000,000,000 X Pi) plus the 8 shells. The first shell is 10,000,000,000 miles The second is ten times that and third ten times that ,etc

This is 29 X 10,000,000,000 X 2 X Pi plus (4,000,000,000 X Pi ) = 1,834,690,110,000

Now we divide by 360 and multiply by 89.9999999999 or even 90 degrees gives us 458,672,527.4

Now divide by our decimal gives us 209,964,688.2 which is circumference of some planetary body at 80.38164599 degree of the universe.

We saw that Satyaloka was at 81.9 degrees-probably these two numbers should be the same. Now a mathematician can understand how he could work backwards from Vaikuntha to shore up the numbers.

Later another opportunity to shore up the numbers will present itself. This completes the first half of the presentation The Distances to the Planets by Mayesa dasa working under the direction of His Divine Grace A. C. Bhaktivedanta Swami, Founder-Acharya of ISKCON.

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